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首页> 外文会议>PIERS 2011 Marrakesh;Progress in electromagnetics research symposium >Quantum Mechanics Suggests that Photons with Different Energy Do Not Travel at the Same Speed
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Quantum Mechanics Suggests that Photons with Different Energy Do Not Travel at the Same Speed

机译：量子力学建议具有不同能量的光子不能以相同的速度传播

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Heisenberg's Uncertainty Principle states that time (△_T) and energy (△_E) are two parameters canonically conjugated and each other correlated by the well known Heisenberg's equation: △_e · △_t > h/2π, where h is the Planck's constant. Hence we know that the members on the left are inversely proportional, thus as one of them increases the other will have to decrease proportionally. Besides if we consider photons (Ps) with different energy, those having a bigger energy will travel in a shorter time, and vice versa. As we know the P also carries a momentum (p), divided by the wavelength (λ): p = h/λ. Therefore, p is not constant for the electromagnetic-waves, but is inversely proportional to λ. Let us calculate the p of the P travelling with a radio wave, where A is equal to 1 cm: p = 6.625 -KT~(-27) [erg ·s]/1 [cm]. Since 1 erg = g · cm/s~2 · cm, we can write: p = 6.625 · 10~(-27) [g · cm~2/s]/1 [cm], p = 6.625·10~(22) [g·cm/s]. The mean P's p of the visible light will be: p = 6.625 · 10~(-27) [erg · s]/5 · 10~(-5) [cm], p = 1.325 ·10~(-27) [g·cm~2/s]/10~(-5) [cm], we have: p = 1.325 · 10~(-22) [g · cm/s]. whereas, let us calculate the p of a P travelling with a γ ray, with λ = 10~(-12) [cm]: p = 6.625 · 10~(-27) [erg · s]/ 10~(-12) [cm] = 6.625 · 10~(-15) [g · cm/s]. That is, the p of a γP is ten millions bigger than the p of a mean P of visible light, and 1000 billiards bigger of the p of a radio P! We should consider that the p is a motion magnitude, thus the bigger a P's p the bigger the motion: that is the P's motion is not the same for all Ps, it is inversely proportional to the A of the considered band, along with the well known equation: p - mv, hence we know that the velocity (v) of a particle, in a given direction, is directly proportional to its p.
机译：海森堡的不确定性原则指出，时间（△_T）和能量（△_E）是两个参数正则共轭，并且通过众所周知的海森堡等式相互关联：△_e·△_t> h /2π，其中h是普朗克常数。因此，我们知道左边的成员成反比，因此，当其中一个成员增加时，另一个成员就必须成比例地减少。此外，如果我们考虑具有不同能量的光子（Ps），则能量更大的光子将在更短的时间内传播，反之亦然。众所周知，P还带有一个动量（p），除以波长（λ）：p = h /λ。因此，p对于电磁波不是恒定的，而是与λ成反比。让我们计算通过无线电波传播的P的p，其中A等于1 cm：p = 6.625 -KT〜（-27）[erg·s] / 1 [cm]。由于1 erg = g·cm / s〜2·cm，我们可以这样写：p = 6.625·10〜（-27）[g·cm〜2 / s] / 1 [cm]，p = 6.625·10〜（ 22）[g·cm / s]。可见光的平均P p为：p = 6.625·10〜（-27）[erg·s] / 5·10〜（-5）[cm]，p = 1.325·10〜（-27）[ g·cm〜2 / s] / 10〜（-5）[cm]，我们有：p = 1.325·10〜（-22）[g·cm / s]。但是，让我们计算出随γ射线传播的P的p，其中λ= 10〜（-12）[cm]：p = 6.625·10〜（-27）[erg·s] / 10〜（-12 ）[cm] = 6.625·10〜（-15）[g·cm / s]。也就是说，γP的p比可见光的平均P的p大一千万，比无线电P的p大1000台球！我们应该认为p是运动幅度，因此P的p越大，运动也越大：即P的运动对于所有Ps都不相同，它与所考虑频带的A成反比，并且与众所周知的等式：p-mv，因此我们知道，粒子在给定方向上的速度（v）与它的p成正比。

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