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Changes in the processor position

机译：处理器位置的变化

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The news is that Intel has bowed to the inevitable and announced plans for 64bit extensions to its standard x86 processor instruction set. This means in the long term a 64bit version of its existing x86 architecture evolving out of the Pentium family. Like several others, I predicted this nearly two years ago, because I didn't believe the Itanium 64bit architecture would be a major success. Before looking at the reasons for this and the possible future success of Intel's two 64bit offerings, it is worth making clear just what the difference is between them. The first IBM PCs used a 16bit processor from Intel, the 80186. Such a processor operates a set of instructions that are precisely defined, and it is large collections of these instructions that make up the software running on a PC. The original chip was a bit of a hybrid, being really an 8bit processor with 16bit extensions. The bit-size mainly refers to the size of the registers in the processor, and therefore the maximum size of data elements it can handle - this also affects the range and accuracy of numerical information it can process.
机译：消息传出，英特尔已经屈服于不可避免的事情，并宣布了对其标准x86处理器指令集进行64位扩展的计划。从长远来看，这意味着其现有的x86架构的64位版本将逐渐脱离奔腾系列。像其他几个应用程序一样，我将近两年前对此进行了预测，因为我不认为Itanium 64位体系结构会取得重大成功。在探讨造成这种情况的原因以及英特尔的两个64位产品未来可能取得成功之前，有必要弄清楚它们之间的区别是什么。第一台IBM PC使用的是Intel的16位处理器80186。这种处理器运行一组精确定义的指令，这些指令的大量集合构成了PC上运行的软件。原始芯片有点混合，实际上是带有16位扩展的8位处理器。位大小主要是指处理器中寄存器的大小，因此它可以处理的数据元素的最大大小-这也影响它可以处理的数字信息的范围和准确性。

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