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首页> 外文期刊>Defence science journal >A New Method for Testing Two Binomial Samples with its Application in Statistical Quality Control
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A New Method for Testing Two Binomial Samples with its Application in Statistical Quality Control

机译：一种测试两个二项式样本的新方法及其在统计质量控制中的应用

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A new method for comparing the proportions observed in two binomial samples involved the characters, say A and B with probabilities p & q has been given in this paper. This method provides the basis for a more reliable comparison than the usual 2X2x/sup/2-contingency test. Taking the samples in order of occurrence to be x1,x2,x3....xn; y1,y2,....yn, the tests depend on the statics Xs and Ys which are based on a system of scoring sigma(xk-y1) or sigma|xk-y1| where |k-l|&=s, a constant. The score for (xk-y1) is zero for combination AA or BB and is+1 or-1 if the combination is AB or BA. Similarly |xk-Y1| is zero in the first case and +1 in the latter two cases. The tests have been illustrated for examining the percentage of defectives produced in two machines. The applications of the tests in psychological investigation have also been explained with reference to the data discussed by McNemar.
机译：一种比较两个二项式样本中观察到的比例的新方法涉及到字符A和B（概率为p＆amp; p）。本文已经给出了q。这种方法提供了比常规2X2x / sup / 2偶然性测试更可靠的比较的基础。以出现的顺序将样本取为x1，x2，x3 .... xn; y1，y2，.... yn，测试取决于静态Xs和Ys，它们基于对sigma（xk-y1）或sigma | xk-y1 |评分的系统其中| k-1 | ＜s，是常数。对于组合AA或BB，（xk-y1）的分数为零;如果组合为AB或BA，则分数为+1或-1。类似| xk-Y1 |在第一种情况下为零，在后两种情况下为+1。举例说明了测试以检查两台机器中产生的次品百分比。还参考了McNemar讨论的数据对测试在心理调查中的应用进行了解释。

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