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首页> 外文期刊>Electrical Engineers - Part III: Radio and Communication Engineering, Journal of the Institution of >The propagation of electric waves in a rectangular wave guide
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The propagation of electric waves in a rectangular wave guide

机译：电波在矩形波导中的传播

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This paper calculates the field, inside a rectangular wave guide, produced by a given set of currents at the origin. In particular, if the guide is excited by a single current filament on its mid-line then the field is found per unit current in this filament and also the radiation resistance of the filament. The solution is generalized to apply to a guide with a closed end. In Appendix 8.2 is calculated the field per unit current when the wave guide is very narrow, being then commonly called an attenuator. The solution for the guide is more complete than those which are common knowledge, in so far as the field is related to the current producing it, and this extension may be novel. In order to assess the sensitiveness of the classic solution to the exact form of the guide, the solution is found for a guide which has a vanishingly small taper. Then it is found that perfect cut-off cannot occur even when the width of the guide at the exciting filament is less than ??: the explanation is that in such a guide of infinite length there is often a point at which the width exceeds ??. It seems probable from this that complete cut-off will not occur if the generator is situated in a length of guide whose width is less than ??, provided this length is joined to a guide whose width exceeds ??. However, it appears that the expression for the radiation resistance of a current sheet, with sinusoidal loading, is general and applies to a guide having any taper, and in particular when the taper is zero and the sides have become parallel. It is concluded from this that the expressions for radiation resistance are very tolerant to small imperfections in the shape of the guide, and, in general, that the well-known and classic solution is very reliable for practical application, provided only that the cut-off property is not interpreted with complete rigour. For the sake of completeness the formal solution is recorded for a current filament at any point in a tapered guide which has a co-nnvex back of any radius; and also the solution for a current enclosed in a box having two sides which are arcs of concentric circles of any radius and two sides which are any radii of these circles. These two solutions are thought to be novel.
机译：本文计算了矩形波导内部由原点给定电流产生的磁场。特别地，如果引导件在其中线被单个电流灯丝激发，则在该灯丝中发现每单位电流的磁场以及灯丝的辐射电阻。该解决方案一般适用于具有封闭端的导轨。在附录8.2中，计算了当波导非常窄时（通常称为衰减器）时每单位电流的磁场。该指南的解决方案比一般知识的解决方案更为完善，只要涉及到与该领域相关的领域，该扩展可能是新颖的。为了评估经典解决方案对指南的确切形式的敏感性，我们找到了一种锥度逐渐减小的指南解决方案。然后发现，即使在激励灯丝处的导向器的宽度小于Δθ，也不能发生完美的切断：解释是，在这种无限长的导向器中，经常会出现宽度超过λ的点。 ？由此看来，如果发生器位于宽度小于Δθ的导向件的长度中，并且该长度与宽度超过Δθ的导向件连接，则似乎完全切断将不会发生。然而，似乎具有正弦负载的电流板的抗辐射性的表述是通用的，并且适用于具有任何锥度的导向装置，特别是当锥度为零且侧面已经平行时。由此得出的结论是，抗辐射的表达式非常容忍导轨形状中的小缺陷，并且，通常，众所周知的经典解决方案对于实际应用是非常可靠的，前提是切割必须off属性不能完全严格解释。为了完整起见，在锥形导向器中的任何点都记录了当前灯丝的正式解，该导向器具有任意半径的后凸面。以及一种解决方案，该电流被封闭在具有两个侧面的盒子中，该侧面是任意半径的同心圆弧，而侧面是这些圆的任何半径。这两个解决方案被认为是新颖的。

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