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Optimization of CaO-catalyzed sunflower oil methanolysis with crude biodiesel as a cosolvent

机译:粗生物柴油为助溶剂优化CaO催化的葵花籽油甲醇分解

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摘要

Crude biodiesel was proven as a cosolvent in the methanolysis of sunflower oil catalyzed by calcined CaO. This reaction was modeled and optimized statistically in terms of reaction temperature (33.2-66.8 degrees C), methanol-tooil molar ratio (3.5:1-8.5:1) and catalyst concentration (0.219-1.065 mol/L). The cosolvent loading was 10 wt% (based on oil weight). The optimum reaction conditions were found to be: the methanol-to-oil molar ratio of 7.1:1, the catalyst concentration of 0.74 mol/L and the reaction temperature 52 degrees C, ensuring the best esters content of 99.8%, for the reaction time of 1.5 h, which is close to the reported experimental value of 98.9%. Also, the used catalyst was recycled with no additional treatment in the further four consecutive cycles under the following reaction conditions: methanol-to-oil molar ratio 6:1, the concentration of catalyst 0.642 mol/L (only in the first run), the reaction temperature 50 degrees C, cosolvent-crude biodiesel loading 10 wt% to oil weight. The second recycling reaction provided the highest FAME content of 97.7% after 5 h.
机译:粗制生物柴油已被证明是煅烧CaO催化葵花籽油甲醇分解中的助溶剂。根据反应温度(33.2-66.8摄氏度),甲醇与油的摩尔比(3.5:1-8.5:1)和催化剂浓度(0.219-1.065 mol / L)对反应进行建模和统计优化。助溶剂负载量为10 wt%(基于油重)。发现最佳反应条件为:甲醇与油的摩尔比为7.1:1,催化剂浓度为0.74 mol / L,反应温度为52℃,确保反应的最佳酯含量为99.8%。时间为1.5小时,接近报道的实验值98.9%。同样,在以下反应条件下,使用的催化剂在另外四个连续循环中无需进一步处理即可再循环:甲醇与油的摩尔比为6:1,催化剂的浓度为0.642 mol / L(仅在第一次运行中),反应温度为50摄氏度,助溶剂粗制生物柴油占油重的10重量%。 5小时后,第二次循环反应的最高FAME含量为97.7%。

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