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On the number of words containing the factor (aba)~k

机译:关于包含因子(aba)〜k的单词数

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In this paper a recurrence relation satisfied by the number L(n) of words of length n over an alphabet A of cardinality m (m≥2) not containing the factor (aba)k (a≠b) is deduced. Let kn be a sequence of positive integers. From [I. Tomescu, A threshold property concerning words containing all short factors, Bull. EATCS 64 (1998) 166–170] it follows that if lim sup_n →∞k(n)/ln n <1/(3 in m) then almost all words of length n over A contain the factor (aba)~(kn) as n→∞. Using the properties of the roots of the recurrence satisfied by L(n) it is shown that if lim sup_n →∞k(n)/in n>1/(3 in m) then this property is false. Moreover, if lim_n →∞(in n-3k in m)= η ∈R then lim_n→∞|W(n, (aba))~(k_n), A|/m~n=1-exp(-(1-1/m~3)exp(η), where W(n,(aba))~(K~n, A) denotes the set of words of length n over A containing the factor (aba)~(kn).
机译:本文推导了一个在不包含因子(aba)k(a≠b)的基数为m(m≥2)的字母A上长度为n的单词的数目L(n)满足的递归关系。令kn为正整数序列。从[I. Tomescu,涉及包含所有短因子的单词的阈值属性,Bull。 EATCS 64(1998)166–170]得出结论,如果lim sup_n→∞k(n)/ ln n <1 /(3 in m),那么在A上几乎所有长度为n的单词都包含因子(aba)〜(kn )为n→∞。利用L(n)满足的递归根的性质,可以证明,如果lim sup_n→∞k(n)/ in n> 1 /(3 in m),则该性质为假。此外,如果lim_n→∞(在m中的n-3k中)=η∈R,则lim_n→∞| W(n,(aba))〜(k_n),A | / m〜n = 1-exp(-(1 -1 / m〜3)exp(η),其中W(n,(aba))〜(K〜n,A)表示长度为n的单词在A上的集合,其中包含因子(aba)〜(kn)。

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