首页> 外国专利> AUSTENITIC STAINLESS STEEL EXCELLENT IN NEUTRON IRRADIATION EMBRITTLEMENT-RESISTING PROPERTY

AUSTENITIC STAINLESS STEEL EXCELLENT IN NEUTRON IRRADIATION EMBRITTLEMENT-RESISTING PROPERTY

机译:中子辐照耐蚀性能中的奥氏体不锈钢优良

摘要

PURPOSE:To prevent neutron irradiation embrittlement by incorporating specific percentage of C, Si, Mn, Cr, Ni, N, and B which is an essential component and has 11B in a ratio higher than the natural abundance ratio, or the like, so as to reduce 10B present in steel. CONSTITUTION:The titled stainless steel has a composition containing, by weight, =0.1% C, =1% Si, =2% Mn, 16-26% Cr, 6-18% Ni, =0.2% N and, as an essential component, 0.0001-0.01% specific B, also containing, as optional components, 0.01-0.5% Ti and/or 0.01-1% Nb, and having the balance Fe. The above-mentioned B has a ratio of B with 11 isotopic mass number to B with 10 isotopic mass number of =9. In the above steel, owing to the raw material containing B having 11B in a ratio higher than the natural abundance ratio, a harmful effect of 10B of causing the occurrence of He by the nuclear transformation by neutron irradiation is removed, so that neutron irradiation embrittlement can be prevented.
机译:目的:通过掺入一定百分比的C,Si,Mn,Cr,Ni,N和B来防止中子辐照脆化,C,Si,Mn,Cr,Ni,N和B是必不可少的成分,并且其11 B的比例高于自然丰度比,等等,以减少钢中存在的10B。组成:标题不锈钢具有以下组成:按重量计,<= 0.1%C,<= 1%Si,<= 2%Mn,16-26%Cr,6-18%Ni,<= 0.2%N和作为必不可少的组分,0.0001-0.01%的特定B,还包含0.01-0.5%的Ti和/或0.01-1%的Nb作为可选组分,余量为Fe。上述B的同位素质量数为11的B与同位素质量数为10的B的比率≥9。在上述钢中,由于含有11 B的比例高于自然丰度比的B的原料,消除了10 B通过中子辐照引起的核转化引起He产生的有害作用。 ,从而可以防止中子辐照脆化。

著录项

相似文献

  • 专利
  • 外文文献
  • 中文文献
获取专利

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号