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一株纤维素高产菌株的鉴定及发酵条件优化

         

摘要

从实验室自制醋中筛选出1株纤维素高产菌株J2,经形态学特征及分子生物学鉴定,确定为汉森氏葡糖醋杆菌(Gluconacetobacter hansenii,GenBank登录号为GU213109).通过PB(Plackett-Burman)和BB(Box-Behnken)试验设计优化菌株J2的发酵培养条件,结果表明,培养基中酵母膏和无水乙醇的含量对BC(细菌纤维素,bacterial cellulose)产量影响极显著,ZnSO4的含量影响显著.通过多元二次方程方差分析及回归方程系数显著性检验,表明所建模型与实际拟合良好,且发酵培养基优化后配方中酵母膏3.3 g/L,ZnSO40.9 g/L,无水乙醇0.7%;使用优化后的发酵培养基,菌株J2的BC产量增加到10.41 g/100 mL,提高了22.18%.发酵动力学试验表明,菌株J2最佳发酵时间为7 d,BC产量可达12 g/100 mL.%A high-yield bacterial cellulose (BC)-producing strain named J2 was isolated from lab homemade vinegar. It was identified as Gluconacetobacter hansenii (GenBank accession GU213109) by morphological characteristics and molecular biological identification. Additionally, the fermentation conditions of strain J2 were studied by PB and BB experiments. The results showed that the contents of yeast extract and anhydrous al-cohol had extremely significant influence on BC yield. Moreover, the data of regression equation of cultivation and regression coefficients and significance of the cultivation indicated that the established model agreed well with the practice, and the optimum fermentation medium contained yeast extract 3.3 g/L, ZnSO40.9 g/L and an-hydrous alcohol 0.7%. Under the optimum fermentation conditions, BC yield could reach to 10.41 g/100 mL, which increased by 22.18%. Finally, the results of fermenting kinetic experiment showed that the optimum fer-mentation time was 7 d, and BC yield was about 12 g/100 mL at this time.

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