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Answer 1- The capacitance of the plates drops with increasing distance, so the voltage between them rises, because the charge doesn't change and the voltage is equal to the charge divided by the capacitance. At first, while the plate spacing is still small relative to their diameter. The capacitance is proportional to the inverse of the spacing, so the voltage rises linearly with the spacing. However, as the spacing becomes larger, the capacitance drops more slowly and the voltage rises at a lower rate as well. While the plate spacing is small, the electric field is almost entirely directly between the two plates, with only minor "fringing" effects at the edges. Since the voltage rise is proportional to the distance in this regime, the electric field (in volts per meter) remains essentially constant. However, once the plate spacing becomes comparable to the diameter of the plates, and fringing effects begin to dominate, the field begins to spread out and weaken. Ultimately, at very large distances, at which the plates themselves can be considered points, the voltage is essentially constant, and the field strength directly between them becomes proportional to the inverse of the distance.
机译:答案1-极板的电容随着距离的增加而下降,因此它们之间的电压会上升,因为电荷没有变化,并且电压等于电荷除以电容。首先,虽然板间距相对于其直径仍然很小。电容与间隔的倒数成正比,因此电压随间隔线性增加。但是,随着间距变大,电容下降得更慢,电压也以较低的速率上升。当板间距很小时,电场几乎完全在两个板之间直接产生,边缘处只有很小的“边缘”效应。由于在这种情况下电压上升与距离成正比,因此电场(以伏特/米为单位)保持基本恒定。但是,一旦板间距变得与板的直径相当,并且边缘效应开始占主导地位,该场便开始扩展并减弱。最终,在极长的距离处(板本身可以视为点),电压基本恒定,并且板之间的场强与该距离的倒数成正比。

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    《Circuit cellar》 |2019年第343期|78-78|共1页
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