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Total Chromatic Number of Δ-Claw-Free 3-Degenerated Graphs

机译:无Δ爪的3退化图的总色数

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The total chromatic number χ"(G) of a graph G is the minimum number of colors needed to color the elements (vertices and edges) of G such that no incident or adjacent pair of elements receive the same color Let G be a graph with maximum degree Δ(G). Considering a total coloring of G and focusing on a vertex with maximum degree. A vertex with maximum degree needs a color and all Δ(G) edges incident to this vertex need more Δ(G) + 1 distinct colors. To color all vertices and all edges of G, it requires at least Δ(G) + 1 colors. That is, χ"(G) is at least Δ(G) + 1. However, no one can find a graph G with the total chromatic number which is greater than Δ(G) + 2. The Total Coloring Conjecture states that for every graph G, χ"(G) is at most Δ(G) + 2. In this paper, we prove that the Total Coloring Conjectur for a Δ-claw-free 3-degenerated graph. That is, we prove that the total chromatic number of every Δ-claw-free 3-degenerated graph is at most Δ(G) + 2.
机译:图G的总色数χ“(G)是为G的元素(顶点和边缘)着色所需的最小颜色数,以便没有入射或相邻元素对接收相同的颜色。最大度数Δ(G)。考虑G的总着色并关注最大度数的顶点。最大度数的顶点需要颜色,入射到该顶点的所有Δ(G)边都需要更多Δ(G)+1要为G的所有顶点和所有边缘着色,至少需要Δ(G)+ 1种颜色。也就是说,χ“(G)至少为Δ(G)+1。但是,没有人找不到图。 G的总色数大于Δ(G)+2。总着色猜想表明,对于每个图G,χ“(G)最多为Δ(G)+2。在本文中,我们证明了Δ无爪3退化图的总着色猜想,也就是说,我们证明每个Δ无爪3退化图的总色数最多为Δ(G)+ 2。

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