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1-azonia-2-boratanaphthalenes

机译:1-氮杂-2-硼萘

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摘要

The 1-azonia-2-boratanaphthalenes (NH)(BX)C8H6 can be synthesized from 2-aminostyrene and the dihaloboranes XBHal(2) (1-4: X = Cl, Br, iPr, tBu). Further derivatives (NH)(BX)C8H6 are obtained from 1 by replacing Cl by alkoxy or alkyl groups [5-8: X = OMe, OtBu, Me, (CH2)(3)NMe2]. The hydrolysis of 1 gives a mixture of the bis(azoniaboratanaphthyl) oxide [(NH)BC8H6](2)O (9) and the hydroxy derivative (NH)[B(OH)]C8H6 (10). The diboryl oxide 9 crystallizes in the space group C2/c. The lithiation of 4 at the nitrogen atom gives [NLi(tmen)](BtBu)C8H6 (11), which upon reaction with the diborane(4) B2Cl2(NMe2)(2) yields the 1,2-bis(azoniaboratanaphtbyl)diborane B-2[N(BtBu)C8H6](2)(NMe2)(2) (12). The 2-chloro-1-methyl-4-phenyl derivative (NMe)(BCl)-C8H5Ph (13) of the parent (NH)(BH)C8H6 can be synthesized from the aminoborane BCl2(NMePh) and phenylethyne. Substitution of Cl in 13 gives the derivatives (NMe)(BX)C8H5Ph [14-20: X = N(SiMe3)(2), Me, Et, iBu, tBu, CH2SiMe3, Ph] and the reaction of 13 with Li2O affords the bis(azoniaboratanaphthyl) oxide [(NMe)BC8H5Ph](2)O (21). The reaction of 16 or 19 with [(MeCN)(3)Cr(CO)(3)] yields the complexes [{(NMe)(BX)-C8H5Ph} Cr(CO)(3)] (22, 23: X = Et, CH2SiMe3) in which the chromium atom is hexahapto bound to the homoarene part of 16 or 19, respectively. The complex 23 crystallizes in the space group P2(1)/c. Upon reaction of the phenols para-C6H4R(OH) with the aryldichloroboranes ArBCl2 and subsequent condensation of the products with phenylethyne, the 1-oxonia-2-boratanaphthalenes O(BAr)C8H4RPh with R in position 6 and Ph in position 4 are formed (24-26: Ar = Ph, R = H, Me, OMe; 27-29: Ar = C6F5, R = H, Me, OMe). The azoniaboratanaphthalenes 1-23 were characterized by NMR methods.
机译:可以从2-氨基苯乙烯和二卤硼烷XBHal(2)(1-4:X = Cl,Br,iPr,tBu)合成1-azonia-2-boratanaphthalenes(NH)(BX)C8H6。通过用烷氧基或烷基取代Cl [5-8:X = OMe,OtBu,Me,(CH2)(3)NMe2],从1获得其他衍生物(NH)(BX)C8H6。 1的水解得到双(氮杂硼烷基萘基萘)氧化物[(NH)BC8H6](2)O(9)和羟基衍生物(NH)[B(OH)] C8H6(10)的混合物。二氧化硼硼烷9在空间群C2 / c中结晶。在氮原子上的4锂化生成[NLi(tmen)](BtBu)C8H6(11),与乙硼烷(4)反应后,B2Cl2(NMe2)(2)生成1,2-双(氮杂硼烷基萘基)二硼烷B-2 [N(BtBu)C8H6](2)(NMe2)(2)(12)。母体(NH)(BH)C8H6的2-氯-1-甲基-4-苯基衍生物(NMe)(BCl)-C8H5Ph(13)可以由氨基硼烷BCl2(NMePh)和苯乙炔合成。 Cl被13取代得到衍生物(NMe)(BX)C8H5Ph [14-20:X = N(SiMe3)(2),Me,Et,iBu,tBu,CH2SiMe3,Ph],13与Li2O的反应得到双(氮杂硼烷基萘基)氧化物[(NMe)BC8H5Ph](2)O(21)。 16或19与[(MeCN)(3)Cr(CO)(3)]的反应生成络合物[{(NMe)(BX)-C8H5Ph} Cr(CO)(3)](22,23:X = Et,CH 2 SiMe 3),其中铬原子六价键合至16或19的均芳烃部分。络合物23在空间群P2(1)/ c中结晶。在苯酚对-C6H4R(OH)与芳基二氯硼烷ArBCl2反应并随后产物与苯乙炔缩合后,形成1-Rxonia-2-boratanaphthalenes O(BAr)C8H4RPh,R处于6位,Ph处于( 24-26:Ar = Ph,R = H,Me,OMe; 27-29:Ar = C 6 F 5,R = H,Me,OMe)。氮杂硼烷基萘1-23通过NMR方法表征。

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