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Almost every 2-SAT function is unate

机译:几乎每个2-SAT功能都是统一的

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摘要

Bollobas Brightwell and Leader [2] showed that there are at most 2((2n) + o(n2)) 2-SAT functions on n variable, and conjectured that in fact the number of 2-SAT functions on n variables is 2((2n) + n) (1 + o(1)). We prove their conjecture. As a corollary of this, we also find the expected number of satisfying assignments of a random 2-SAT function on n variables. We also find the next largest class of 2-SAT functions and show that if k = k(n) is any function with k(n) < n(1/4) for all sufficiently large n, then the class of 2-SAT functions on n variables which cannot be made unate by removing 25k variables is smaller than 2((2n) + n - kn) for all sufficiently large n.
机译:Bollobas Brightwell和Leader [2]表明,在n个变量上最多存在2((2n)+ o(n2))个2-SAT函数,并推测实际上在n个变量上的2-SAT函数数为2(( (2n)+ n)(1 + o(1))。我们证明他们的猜想。作为推论,我们还找到了对n个变量的随机2-SAT函数的满意分配的预期数量。我们还找到第二类最大的2-SAT函数,并证明如果k = k(n)是对于所有足够大的n都具有k(n)

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