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首页> 外文期刊>Electrochimica Acta >Oxidation of formaldehyde and ethanol on Au(111) and Au(111) modified by spontaneously deposited Ru in sulfuric acid solution
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Oxidation of formaldehyde and ethanol on Au(111) and Au(111) modified by spontaneously deposited Ru in sulfuric acid solution

机译：硫酸溶液中自发沉积钌修饰的Au（111）和Au（111）上甲醛和乙醇的氧化

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摘要

The oxidation of formaldehyde and ethanol on both pure Au(111) and Au(111) modified by approximately 0.3 monolayer (ML) of spontaneously deposited Ru was studied by cyclic voltammetry (CV) in 0.5 M H_2SO_4 solution containing either 0.25 M formaldehyde or 0.35 M ethanol. In situ scanning tunneling microscopy (STM) and CV were employed to characterize the Au(111) and Ru/Au(111) surfaces. The oxidation of HCHO on Ru/Au(111) commences at 0.1 V more negative potential than on pure Au(111). From 0.25 to 0.55 V vs. (Ag/AgCl), the reaction occurs with increasing current, showing a peak at a potential of 0.43 V. It is assumed that the increasing anodic activity of the Ru/Au(111) surface is associated with the oxidation of some reaction intermediates, facilitated by the presence of Ru in its metallic state. On the other hand, the oxidation of ethanol on Ru/Au(111) commences at 0.1 V more positive potential than on pure Au(111), and proceeds in the potential region from 0.2 to 0.5 V with significantly smaller currents, showing a peak at 0.43 V. This inhibiting effect is explained by the deactivation of the most active Au(111) step sites by high coverage with Ru islands. The appearance of a small peak at 0.43 V is most likely associated to the oxidation of some intermediates during ethanol oxidation at the Ru/Au step sites formed on the Au(111) terraces by the presence of a small coverage with Ru islands.
机译：通过循环伏安法（CV）在含有0.25 M甲醛或0.35甲醛的0.5 M H_2SO_4溶液中通过循环伏安法（CV）研究了纯的Au（111）和Au（111）上纯净的Au（111）和经约0.3单层（ML）修饰的Au（111）上甲醛和乙醇的氧化M乙醇。原位扫描隧道显微镜（STM）和CV用于表征Au（111）和Ru / Au（111）表面。 Ru / Au（111）上HCHO的氧化开始于负电位比纯Au（111）高0.1V。从（0.25）到0.55 V vs.（Ag / AgCl），反应随电流的增加而发生，在0.43 V的电势上出现一个峰值。假定Ru / Au（111）表面的阳极活性增加与钌在金属状态下的存在促进了某些反应中间体的氧化。另一方面，Ru / Au（111）上乙醇的氧化开始于比纯Au（111）上高0.1 V的正电势，并在0.2-0.5 V的电势区域内以明显较小的电流进行氧化，显示出一个峰值在0.43 V时。这种抑制作用是由于Ru岛的高覆盖率使最活跃的Au（111）台阶位点失活而解释的。在0.43 V处出现一个小峰很可能与乙醇氧化过程中某些中间体的氧化有关，这是由于Ru岛上的覆盖较小，在Au（111）台阶上形成的Ru / Au台阶位上形成了Ru / Au台阶。

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