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首页> 外文期刊>Engineering Fracture Mechanics >Stress intensity factor for a circumferential crack in a finite-length thin to thick-walled cylinder under an arbitrary biquadratic stress distribution on the crack surfaces
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Stress intensity factor for a circumferential crack in a finite-length thin to thick-walled cylinder under an arbitrary biquadratic stress distribution on the crack surfaces

机译：裂纹表面上任意双二次应力分布下有限长薄壁至厚壁圆柱体中周向裂纹的应力强度因子

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摘要

This paper presents the development of a practical method, by using prepared tabulated data, to calculate the mode I stress intensity factor (SIF) for an inner surface circumferential crack in a finite-length cylinder. The crack surfaces are subjected to an axisymmetric stress with an arbitrary biquadratic radial distribution. The method was derived by applying the authors' weight function for the crack. This work is based on the thin shell theory and the Petroski-Achenbach method. Our method is valid over a wide range of mean radius to wall thickness ratio, R_m/W>=1, and for relatively short crack with a/W<=0.5. The difference between the SIF obtained by our method for the geometry and that from finite element analysis is within 5 percent. the method we developed describes the effect that cylinder length gives on the SIF. This effect needs to be considered for cylinders shorter than non-dimensional cylinder length #beta#H <=5.
机译：本文介绍了一种实用的方法，通过使用准备好的表格数据来计算有限长圆柱体内表面圆周裂纹的模式I应力强度因子（SIF）。裂纹表面承受具有任意双二次径向分布的轴对称应力。该方法是通过将作者的权重函数应用于裂缝而得出的。这项工作基于薄壳理论和Petroski-Achenbach方法。我们的方法在较大的平均半径与壁厚比R_m / W> = 1的范围内有效，并且对于a / W <= 0.5的相对较短的裂纹也是有效的。通过我们的几何方法获得的SIF与通过有限元分析获得的SIF之差在5％之内。我们开发的方法描述了圆柱长度对SIF的影响。对于小于无尺寸圆柱体长度＃beta＃H <= 5的圆柱体，需要考虑这种效果。

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