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Reduction of dimensionality in a diffusion search process and kinetics of gene expression

机译:减少扩散搜索过程中的维数和基因表达动力学

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In order to activate a gene in a DNA molecule a specific protein (transcription factor) has to bind to the promoter of the gene. We formulate and partially answer the following question: how much time does a transcription factor, which activates a given gene, need in order to find this gene inside the nucleus of a cell? The estimate based on the simplest model of diffusion gives a very long time of days. We discuss various mechanisms by which the time can be reduced to seconds, in particular, the reduction of dimensionality, in which diffusion takes place, from three-dimensional space to two-dimensional space. The potential needed to keep the diffusing particle in 2D (i.e, at the surface of size L-2 in a volume of size L-3) should scale as U similar to k(B)T lnL. For at = 1 mu m and a target size a = 10 Angstrom we find U = 8k(B)T, i.e., it is a potential strength of the order of the strength of ionic interactions in water. (C) 2000 Elsevier Science B.V. All rights reserved. [References: 38]
机译:为了激活DNA分子中的基因,特定的蛋白质(转录因子)必须与基因的启动子结合。我们提出并部分回答以下问题:激活给定基因的转录因子需要多少时间才能在细胞核内找到该基因?根据最简单的扩散模型进行的估算得出了很长的时间。我们讨论了可以将时间减少到几秒钟的各种机制,特别是从三维空间到二维空间的发生扩散的维数减少。保持扩散粒子处于二维状态(即在大小为L-3的大小为L-2的表面)所需的电势应按与k(B)T lnL相似的U进行缩放。对于at = 1μm和目标尺寸a = 10埃,我们发现U = 8k(B)T,即它是水中离子相互作用强度的潜在强度。 (C)2000 Elsevier Science B.V.保留所有权利。 [参考:38]

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