首页> 外国专利> METHOD FOR DIAGNOSING POTASSIUM DEFICIENCY IN PLANT

METHOD FOR DIAGNOSING POTASSIUM DEFICIENCY IN PLANT

机译:诊断植物钾缺乏症的方法

摘要

PROBLEM TO BE SOLVED: To provide a method for diagnosing potassium deficiency in plant, which does not require experiment or intuition of an agriculture worker and uses an infrared absorption spectrum.SOLUTION: A method for diagnosing potassium deficiency in a plant comprises: a step for preparing a water extract of a plant leaf; a step for measuring an infrared absorption spectrum of the water extract; a step for calculating a difference spectrum based on the infrared absorption spectrum of the water extract and an infrared absorption spectrum of water; a step for correcting a base line of the difference spectrum, for acquiring a correction spectrum; and a step for in the correction spectrum, when there is a peak in a wavelength area of 9.57 μm or more and 9.89 μm or less, and when an area ratio expressed by a formula (1) is equal to or less than a reference value, determining that the plant is potassium deficiency. The area ratio=(a first peak area having a peak top in a wavelength area of 9.16 μm or more and 9.36 μm or less)/(a second peak area having a peak top in a wavelength area of 9.57 μm or more and 9.89 μm or less).SELECTED DRAWING: Figure 2
机译:解决的问题:提供一种不需要植物工人的实验或直觉并且使用红外吸收光谱的植物中钾缺乏症的诊断方法。解决方案:一种植物中钾缺乏症的诊断方法包括:制备植物叶片的水提取物;测量水提取物的红外吸收光谱的步骤;根据水提取物的红外吸收光谱和水的红外吸收光谱计算差光谱的步骤;校正差谱的基线,获取校正谱的步骤;校正光谱的步骤,当在9.57μm以上且9.89μm以下的波长区域中存在峰值,并且由式(1)表示的面积比为基准值以下时,确定植物缺钾。面积比=(在9.16μm以上且9.36μm以下的波长区域具有峰顶的第一峰面积)/(在9.57μm以上且9.89μm的波长区域具有峰顶的第二峰面积。或更少)。选择的图纸:图2

著录项

相似文献

  • 专利
  • 外文文献
  • 中文文献
获取专利

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号