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首页> 外文期刊>Polyhedron: The International Journal for Inorganic and Organometallic Chemistry >Oxidative addition reaction of perfluoro-n-butyl iodide to (COD)PtMe2 to give (COD)PtMe((C4F9)-C-n). The molecular structure of (COD)PtMe2
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Oxidative addition reaction of perfluoro-n-butyl iodide to (COD)PtMe2 to give (COD)PtMe((C4F9)-C-n). The molecular structure of (COD)PtMe2

机译:全氟正丁基碘与(COD)PtMe2的氧化加成反应,得到(COD)PtMe((C4F9)-C-n)。 (COD)PtMe2的分子结构

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摘要

Reaction of (COD)PtMe2 (COD = 1,5-cyclooctadiene) with one molar equivalent of C4F9I in hexanes produces the perfluoroalkylplatinum product (COD)PtMe(C4F9) (1) along with the known Pt(IV) complex [PtMe3I](4). This result stands in contrast to previous reports that attempts to synthesize platinum complexes with fluoroalkyls larger than CF3 gave only inseparable mixtures. An essential condition to the controlled synthesis of 1 is the use of only one equivalent of perfluoroalkyl iodide. Similar reactions reported previously employed an excess of iodoperfluorocarbon, which gave rise to mixtures of products due to successive oxidative addition and reductive elimination reactions. The X-ray crystal structure (COD)PtMe2 was determined. (C) 2002 Elsevier Science Ltd. All rights reserved. [References: 19]
机译:(COD)PtMe2(COD = 1,5-环辛二烯)与一摩尔当量的C4F9I在己烷中的反应产生全氟烷基铂产物(COD)PtMe(C4F9)(1)以及已知的Pt(IV)络合物[PtMe3I]( 4)。该结果与以前的报道相反,以前的报道试图合成具有大于CF3的氟代烷基的铂配合物,只能得到不可分离的混合物。 1受控合成的必要条件是仅使用一当量的全氟烷基碘。先前报道的类似反应使用了过量的碘代氟化碳,由于连续的氧化加成和还原消除反应,生成了产物混合物。测定了X射线晶体结构(COD)PtMe 2。 (C)2002 Elsevier ScienceLtd。保留所有权利。 [参考:19]

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