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首页> 外文期刊>Surface & Coatings Technology >Toluene and 4-chlorotoluene decomposition in air mixture in electron beam generated non-thermal plasma reactor and their by-products identification
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Toluene and 4-chlorotoluene decomposition in air mixture in electron beam generated non-thermal plasma reactor and their by-products identification

机译：电子束非热等离子体反应器中空气混合物中甲苯和4-氯甲苯的分解及其副产物的鉴定

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摘要

Degradation of toluene and 4-chlorotoluene in air mixture was studied by using electron beam generated plasma reactor. It was found that removal efficiency of toluene and 4-chlorotoluene was influenced by radiation dose, i.e. energy deposited in the gas, and their initial concentration. The by-products formed as a result of degradation of toluene or 4-chlorotoluene under electron beam radiation were identified. The mechanism of their degradation was proposed. ~aOH radicals play a main role in degradation process of toluene or 4-chlorotoluene. For degradation of 4-chlorotoluene, reaction of ~aOH radicals with 4-chlorotoluene by hydrogen abstraction from the methyl group, followed by peroxyl radical formation, is a main reaction pathway. 4-chlorobenzaldehyde and 4-chlorobenzyl alcohol are formed according to the Russel-mechanism. For degradation of toluene, reaction pathway of ~aOH radicals with toluene by hydrogen abstraction from the methyl group plays an important role. Besides it, there are the other two important reaction pathways. One is reaction of ~aOH radical addition and H atom abstraction from benzene ring; the other is ~aOH-adduct reaction. Cresol, nitrotoluene and ring cleavage products are formed from these two reaction pathways. Since Cl is more electronegative than H, H atom abstraction from -CH_3 by ~aOH radicals from toluene (HC_6H_4CH_3) is easier than from 4-chlorotoluene (ClC_6H_4CH_3), this may explain why the decomposition efficiency of toluene is slightly higher than that of 4-chlorotoluene in an air mixture under EB radiation.
机译：用电子束产生等离子体反应器研究了空气混合物中甲苯和4-氯甲苯的降解。发现甲苯和4-氯甲苯的去除效率受辐射剂量即气体中沉积的能量及其初始浓度的影响。鉴定了在电子束辐射下由于甲苯或4-氯甲苯的降解而形成的副产物。提出了它们降解的机理。 〜aOH自由基在甲苯或4-氯甲苯的降解过程中起主要作用。对于4-氯甲苯的降解，主要的反应途径是通过从甲基上夺氢，使〜aOH自由基与4-氯甲苯反应，然后形成过氧自由基。根据罗素机理形成4-氯苯甲醛和4-氯苄醇。对于甲苯的降解，〜aOH自由基与甲苯通过从甲基中吸氢的反应途径起着重要的作用。除此之外，还有另外两个重要的反应途径。一个是〜aOH自由基加成反应和从苯环夺取H原子的反应;另一个是〜aOH加成反应。由这两个反应途径形成甲酚，硝基甲苯和环裂解产物。由于Cl比H更具负电性，因此从甲苯（HC_6H_4CH_3）的〜aOH基团从-CH_3提取H原子比从4-氯甲苯（ClC_6H_4CH_3）提取H原子更容易，这可以解释为什么甲苯的分解效率略高于4 EB辐射下空气混合物中的-氯甲苯。

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